Problem: The active agent in many hair bleaches is hydrogen peroxide. The amount of H2O2 in 14.8 g of hair bleach was determined by titration with a standard potassium permanganate solution:2 MnO4 −(aq) + 5 H2O2(aq) + 6 H+(aq) ⟶ 5 O2(g) + 2 Mn2+(aq) + 8 H2O(l) How many moles of MnO4−  were required for the titration if 43.2 mL of 0.105 M KMnO4 was needed to reach the end point?

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The active agent in many hair bleaches is hydrogen peroxide. The amount of H2O2 in 14.8 g of hair bleach was determined by titration with a standard potassium permanganate solution:

2 MnO4 (aq) + 5 H2O2(aq) + 6 H+(aq) ⟶ 5 O2(g) + 2 Mn2+(aq) + 8 H2O(l) 

How many moles of MnO4  were required for the titration if 43.2 mL of 0.105 M KMnO4 was needed to reach the end point?

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