Problem: Fluoride ion is poisonous in relatively low amounts: 0.2 g of F − per 70 kg of body weight can cause death. Nevertheless, in order to prevent tooth decay, F− ions are added to drinking water at a concentration of 1 mg of F− ion per L of water. How many liters of fluoridated drinking water would a 70-kg person have to consume in one day to reach this toxic level? How many kilograms of sodium fluoride would be needed to treat an 8.50×107-gal reservoir?

🤓 Based on our data, we think this question is relevant for Professor Hoeger's class at UCSD.

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Part A

mass body (poisonous level) → g F- (conversion factor) → mg F- (concentration) → L water


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Problem Details

Fluoride ion is poisonous in relatively low amounts: 0.2 g of F per 70 kg of body weight can cause death. Nevertheless, in order to prevent tooth decay, F ions are added to drinking water at a concentration of 1 mg of F ion per L of water. How many liters of fluoridated drinking water would a 70-kg person have to consume in one day to reach this toxic level? How many kilograms of sodium fluoride would be needed to treat an 8.50×107-gal reservoir?

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Based on our data, we think this problem is relevant for Professor Hoeger's class at UCSD.

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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.