Balanced equation: 2 HCl(aq) + CaCO3(s)⟶ CaCl2(aq) + CO2(g) + H2O(l)
Mole to mole comparison: 1 mole CaCO3 reacts with 2 moles of HCl
Solving for volume of 0.383 M HCl:
How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO3?
2 HCl(aq) + CaCO3(s) ⟶ CaCl2(aq) + CO2(g) + H2O(l)
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Based on our data, we think this problem is relevant for Professor Billman's class at Abilene Christian University.
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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.