Problem: How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO3?2 HCl(aq) + CaCO3(s) ⟶ CaCl2(aq) + CO2(g) + H2O(l)

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Balanced equation2 HCl(aq) + CaCO3(s) CaCl2(aq) + CO2(g) + H2O(l)


Mole to mole comparison: 1 mole CaCO3 reacts with 2 moles of HCl


Molarity (M) =moles of soluteLiters of solution


Solving for volume of 0.383 M HCl: 

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Problem Details

How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO3?

2 HCl(aq) + CaCO3(s) ⟶ CaCl2(aq) + CO2(g) + H2O(l)

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Our tutors have indicated that to solve this problem you will need to apply the Solution Stoichiometry concept. You can view video lessons to learn Solution Stoichiometry. Or if you need more Solution Stoichiometry practice, you can also practice Solution Stoichiometry practice problems.

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Based on our data, we think this problem is relevant for Professor Billman's class at Abilene Christian University.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.