# Problem: How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO3?2 HCl(aq) + CaCO3(s) ⟶ CaCl2(aq) + CO2(g) + H2O(l)

###### FREE Expert Solution

Balanced equation2 HCl(aq) + CaCO3(s) CaCl2(aq) + CO2(g) + H2O(l)

Mole to mole comparison: 1 mole CaCO3 reacts with 2 moles of HCl

Solving for volume of 0.383 M HCl:

90% (441 ratings) ###### Problem Details

How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO3?

2 HCl(aq) + CaCO3(s) ⟶ CaCl2(aq) + CO2(g) + H2O(l)

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Solution Stoichiometry concept. You can view video lessons to learn Solution Stoichiometry. Or if you need more Solution Stoichiometry practice, you can also practice Solution Stoichiometry practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Billman's class at Abilene Christian University.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.