Problem: A sample of 0.600 mol of a metal M reacts completely with excess fluorine to form 46.8 g of MF2.What element is represented by the symbol M?

FREE Expert Solution

We have to determine which metal is present in the compound MF2. So, Let’s start by writing a chemical equation for the formation of MF2.


<math xmlns="http://www.w3.org/1998/Math/MathML"><menclose mathcolor="#0000FF" notation="box"><mi mathvariant="normal">M</mi><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><msub><mi mathvariant="normal">F</mi><mn>2</mn></msub><mo>&#xA0;</mo><mo>&#x2192;</mo><mo>&#xA0;</mo><msub><mi>MF</mi><mn>2</mn></msub></menclose></math>


To get ahead with this problem, we will first write a dissociation reaction for this compound. Recall that compounds of metals and halogens dissociate into metal cations and halide anions.


<math xmlns="http://www.w3.org/1998/Math/MathML"><menclose mathcolor="#0000FF" notation="box"><msub><mi>MF</mi><mn>2</mn></msub><mo>&#xA0;</mo><mo>&#x21CC;</mo><mo>&#xA0;</mo><msup><mi mathvariant="normal">M</mi><mrow><mn>2</mn><mo>+</mo></mrow></msup><mo>&#xA0;</mo><mo>+</mo><mo>&#xA0;</mo><mn>2</mn><msup><mi mathvariant="normal">F</mi><mo>-</mo></msup></menclose></math>


Since the metal M has a +2 charge, this means it has lost 2 electrons. This indicates that the metal we are looking for belongs to group II-A.


Now, we will have to determine the molar mass of the metal and predict which metal it is.


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Problem Details

A sample of 0.600 mol of a metal M reacts completely with excess fluorine to form 46.8 g of MF2.

What element is represented by the symbol M?

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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.