We have to determine which metal is present in the compound MF2. So, Let’s start by writing a chemical equation for the formation of MF2.
To get ahead with this problem, we will first write a dissociation reaction for this compound. Recall that compounds of metals and halogens dissociate into metal cations and halide anions.
Since the metal M has a +2 charge, this means it has lost 2 electrons. This indicates that the metal we are looking for belongs to group II-A.
Now, we will have to determine the molar mass of the metal and predict which metal it is.
A sample of 0.600 mol of a metal M reacts completely with excess fluorine to form 46.8 g of MF2.
What element is represented by the symbol M?
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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.