Calculate the following quantity:Number of N atoms...

Question

Calculate the following quantity:Number of N atoms in 92.6 mg of NH 4NO2

Jules Bruno · Accepted Answer

For this problem, we’re being asked to determine the number of carbon (N) atoms found in 92.6 mg of NH4NO2. The flow for this problem will be like this:mg of NH4NO2(mg to g conversion) → g of NH4NO2(molar mass of NH4NO2) → Moles of NH4NO2(mole-to-mole comparison) → Moles of N (Avogadro’s number) → Atoms of N[readmore]• Molar mass of NH4NO2: NH4NO2       2 N × 14.01 g/mol N = 28.02 g/mol                              2 O × 16.00 g/mol O = 32.00 g/mol                              4 H × 1.01 g/mol H = 4.04 g/mol                                         Sum = 64.06 g/molNumber of N atoms in 92.6 mg of NH4NO2• Mole-to-mole comparison: From the molecular formula of butane, NH4NO2, we can do a mole-to-mole comparison and see that there are 2 moles of N in 1 mole of NH4NO2.• Avogadro’s Number: Avogadro’s number gives us the number of entities present in 1 mole of anything: 6.022 × 1023 N atoms in 1 mole N.• 1 mg = 10-3 gNow that we know the values we need, we can now determine the number of N atoms:92.6  mg NH4NO2 ×10-3  g NH4NO21 mg NH4NO2 ×1 mol NH4NO2 64.06 g NH4NO2×2  mol N 1 mol NH4NO2 ×6.022 × 1023 atoms N1  mol N = 1.74 x 1021 atoms NThere are 1.74 x 1021 atoms N in 92.6 mg of NH 4NO2

Problem: Calculate the following quantity:Number of N atoms in 92.6 mg of NH 4NO2

FREE Expert Solution

Problem Details

Problem: Calculate the following quantity:Number of N atoms in 92.6 mg of NH 4NO2

FREE Expert Solution

Problem Details

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