🤓 Based on our data, we think this question is relevant for Professor Veige's class at UF.
Molar mass of Fe(ClO4)3:
Fe(ClO4)3 1 Fe × 14.01 g/mol Fe = 55.85 g/mol
3 Cl × 35.45 g/mol Cl = 106.35 g/mol
12 O × 16.00 g/mol O = 192.00 g/mol
Total: 354.20 g/mol
Calculate the following quantity:
Amount (mol) of compound in 15.8 kg of Fe(ClO4)3
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