# Problem: Calculate the following quantity:Amount (mol) of compound in 15.8 kg of Fe(ClO4)3

###### FREE Expert Solution

Molar mass of Fe(ClO4)3:

Fe(ClO4)3     1 Fe × 14.01 g/mol Fe =   55.85 g/mol

3 Cl  × 35.45 g/mol Cl  = 106.35 g/mol

12 O   × 16.00 g/mol O  = 192.00 g/mol

Total: 354.20 g/mol

80% (387 ratings) ###### Problem Details

Calculate the following quantity:

Amount (mol) of compound in 15.8 kg of Fe(ClO4)3

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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.