Solution: Combining 0.272 mol of Fe₂O₃ with excess carbon produced 17.7 g of Fe. Fe₂O₃ + 3C → 2Fe + 3CO What is the actual yield of iron in moles? What was the theoretical yield of iron in moles? What was the percent yield? 

Problem

Combining 0.272 mol of Fe₂O₃ with excess carbon produced 17.7 g of Fe. 

Fe₂O₃ + 3C → 2Fe + 3CO 

What is the actual yield of iron in moles? 

What was the theoretical yield of iron in moles? 

What was the percent yield? 

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