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Problem: If a solution containing 22.34 g of mercury(lI) acetate is allowed to react completely with a solution containing 6.256 g of sodium dichromate, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction? 

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If a solution containing 22.34 g of mercury(lI) acetate is allowed to react completely with a solution containing 6.256 g of sodium dichromate, how many grams of solid precipitate will be formed? 

How many grams of the reactant in excess will remain after the reaction?