Problem: Zinc reacts with hydrochloric acid according to the reaction equation Zn (s) + 2HCl (aq) → ZnCl2 (aq) + H2 (g) How many milliliters of 5.00 M HCl(aq) are required to react with 4.65 g of an ore containing 44.0% Zn(s) by mass?

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Zinc reacts with hydrochloric acid according to the reaction equation 

Zn (s) + 2HCl (aq) → ZnCl2 (aq) + H2 (g) 

How many milliliters of 5.00 M HCl(aq) are required to react with 4.65 g of an ore containing 44.0% Zn(s) by mass?

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