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Problem: Liquid octane (CH3(CH2)6CH3) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). Suppose 2.28 g of octane is mixed with 4.5 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 2 significant digits.

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FREE Expert Solution

We’re being asked to calculate the mass of carbon dioxide, CO2, that will be formed in the reaction. First, we need to find the chemical equation:

CH3(CH2)6CH3(l) + O2(g) → CO2(g) + H2O(g)


This equation is not yet balanced. To balance it, we have to make sure that the number of elements on both sides is equal.


Balance C: We have 8 C on the reactant side and 1 C on the product side – add a coefficient of 8 to CO2:

CH3(CH2)6CH3(l) + O2(g) → 8 CO2(g) + H2O(g)


Balance H: We have 18 H on the reactant side and 2 H on the product side – add a coefficient of 9 to H2O:

CH3(CH2)6CH3(l) + O2(g) → 8 CO2(g) + 9 H2O(g)


Balance O: We have 2 O on the reactant side and 8(2) + 9 = 25 O on the product side – multiply the entire equation by 2 and add a coefficient of 25 to O2:

CH3(CH2)6CH3(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(g)


Now that we have a balanced equation, we can determine how much CO2 is produced.


Notice that we are given the mass of both reactants: this means we need to determine the limiting reactant, which is the reactant that forms the less amount of product. This is because once the limiting reactant is all used up, the reaction can no longer proceed and make more products.


This means the limiting reactant determines the maximum mass of the product formed.


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Problem Details

Liquid octane (CH3(CH2)6CH3) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). Suppose 2.28 g of octane is mixed with 4.5 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 2 significant digits.


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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.

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Our tutors rated the difficulty ofLiquid octane (CH3(CH2)6CH3) will react with gaseous oxygen ...as medium difficulty.

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Our expert Chemistry tutor, Dasha took 10 minutes and 54 seconds to solve this problem. You can follow their steps in the video explanation above.

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Based on our data, we think this problem is relevant for Professor Li's class at UW-SEATTLE.