Ch.13 - Chemical KineticsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: At a certain temperature the rate of this reaction is second order in H3PO4 with a rate constant of 10.3 M-1 • s-1. 2H3PO4 (aq) →  P2O5 (aq) + 3H2O (aq) Suppose a vessel contains H3PO4 at a concentrat

Problem

At a certain temperature the rate of this reaction is second order in H3PO4 with a rate constant of 10.3 M-1 • s-1

2H3PO4 (aq) →  P2O5 (aq) + 3H2O (aq) 

Suppose a vessel contains H3PO4 at a concentration of 1.29 M. Calculate the concentration of H3PO4 in the vessel 1.00 seconds later. You may assume no other reaction is important. 

Round your answer to 2 significant digits.