Ch.12 - SolutionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Question 9 (10 points) Why is the concentration in the freezing point depression molality instead of molarity? (i) Poor molality isn't used much, so why not here. (ii) Molarity changes with temperature, so is not a good unit for this type of experiment. (iii) The lowercase m looks better in this equation. (iv) when the van't Hoff factor is used molality must be the concentration unit.

Problem

Question 9 (10 points) 

Why is the concentration in the freezing point depression molality instead of molarity? 

(i) Poor molality isn't used much, so why not here. 

(ii) Molarity changes with temperature, so is not a good unit for this type of experiment. 

(iii) The lowercase m looks better in this equation. 

(iv) when the van't Hoff factor is used molality must be the concentration unit.