Problem: At 25°C, the equilibrium partial pressures for the following reaction were found to be PA = 4.19 atm, PB = 5.69 atm, PC = 4.31 atrm, and PD = 4.01 atm. 3A (g) + 2B (g) ⇌ C (g) + 2D (g) What is the standard change in Gibbs free energy of this reaction at 25°C?

FREE Expert Solution
98% (292 ratings)
View Complete Written Solution
Problem Details

At 25°C, the equilibrium partial pressures for the following reaction were found to be PA = 4.19 atm, PB = 5.69 atm, PC = 4.31 atrm, and PD = 4.01 atm. 

3A (g) + 2B (g) ⇌ C (g) + 2D (g) 

What is the standard change in Gibbs free energy of this reaction at 25°C?

Learn this topic by watchingGibbs Free Energy Concept Videos
All Chemistry Practice Problems Gibbs Free Energy Practice Problems
Q.Given that S (g) + O2 (g) → SO2 (g)           ΔrG° = -300.1 kJ/mol-rxn 2S (g) + 3O2 (g) → 2SO3 (g)    ΔrG° = -742.1 kJ/mol-rxn calculate ΔJG° of the f...
Q.For a particular reaction at 127.1°C, ΔG = -500.31 kJ/mol, and ΔS = 868.25 J/(mol • K). Calculate ΔG for this reaction at 12.0°C.
Q.The values of ΔH°rxn and ΔS°rxn for the reaction 2NO (g) + O2 (g) → 2NO2 (g) are -12.0 kJ and -147 J/K. Calculate ΔG° at 298 K for this reaction. 
See all problems in Gibbs Free Energy

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gibbs Free Energy concept. You can view video lessons to learn Gibbs Free Energy. Or if you need more Gibbs Free Energy practice, you can also practice Gibbs Free Energy practice problems.