Ch.14 - Chemical EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The steam reformation reaction is an important source of H2 (at 750°C): CH4 (g) + H2O (g) ⇌ CO (g) + 3H2 (g) Use the following information to calculate Kp (750°C): H2 (g) + 1/2O2 (g) ⇌ H2O (g)                        K1 = 1.56 x 1023 2CH4 (g) + O2 (g) ⇌ 2CO (g) + 4H2 (g)        K2 = 5.90 x 1015

Problem

The steam reformation reaction is an important source of H2 (at 750°C): 

CH4 (g) + H2O (g) ⇌ CO (g) + 3H2 (g) 

Use the following information to calculate Kp (750°C): 

H2 (g) + 1/2O2 (g) ⇌ H2O (g)                        K= 1.56 x 1023 

2CH4 (g) + O2 (g) ⇌ 2CO (g) + 4H2 (g)        K2 = 5.90 x 1015