Ch.6 - Thermochemistry WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Given the following data (1) 2ClF (g) + O2 (g) → Cl2O (g) + OF2 (g)         ΔH°rxn = 167.5 kJ (2) 2F2 (g) + O2 (g) → 2OF2 (g)                          ΔH°rxn = -43.5kJ (3) 2ClF3 (l) + 2O2 (g) → Cl2O (

Problem
Given the following data 

(1) 2ClF (g) + O2 (g) → Cl2O (g) + OF2 (g)         ΔH°rxn = 167.5 kJ 

(2) 2F2 (g) + O2 (g) → 2OF2 (g)                          ΔH°rxn = -43.5kJ 

(3) 2ClF3 (l) + 2O2 (g) → Cl2O (g) + 3OF2 (g)    ΔH°rxn = 394.1 kJ 

Calculate ΔHrxn for the reaction. Show your work! 

ClF (g) + F2 (g) → ClF3 (l)