Problem: The standard electrode potential for the following reaction is -0.13 V.  What is the potential at pH = 13.00? CrO42-(aq) + 4 H2O(l) + 3 e - → Cr(OH)3(s) + 5 OH -(aq)   A. 0.42 B. 0.031 C. -0.031 D. 0.27 E. 2.24

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The standard electrode potential for the following reaction is -0.13 V.  What is the potential at pH = 13.00?

CrO42-(aq) + 4 H2O(l) + 3 e - → Cr(OH)3(s) + 5 OH -(aq)

A. 0.42

B. 0.031

C. -0.031

D. 0.27

E. 2.24

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