Using the standard electrode potentials, determine the cell voltage for the following reaction when [Fe2+] = 0.10 M and [Cd2+] = 1.0 M.
Fe(s) + Cd2+(aq) ⇌ Fe2+(aq) + Cd(s)
Fe2+(aq) + 2 e -→ Fe(s) E° = -0.44 V
Cd2+(aq) + 2 e -→ Cd(s) E° = -0.40 V
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