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Problem: Limestone (CaCO3) reacts with hydrochloric acid according to the equation: CaCO 3 + 2HCl → CaCl2 + H2O + CO2 If 1.00 mol of CO2 has a volume of 22.4 L under the reaction conditions, how many liters of gas can be formed by reaction of 2.30 g of CaCO3 with 2.30 g of HCl? Which reactant is limiting? a. limestoneb. hydrochloric acid 

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Problem Details

Limestone (CaCO3) reacts with hydrochloric acid according to the equation: CaCO 3 + 2HCl → CaCl2 + H2O + CO2 

If 1.00 mol of CO2 has a volume of 22.4 L under the reaction conditions, how many liters of gas can be formed by reaction of 2.30 g of CaCO3 with 2.30 g of HCl? 

Which reactant is limiting? 

a. limestone
b. hydrochloric acid 

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gas Stoichiometry concept. If you need more Gas Stoichiometry practice, you can also practice Gas Stoichiometry practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Tang's class at USF.