Problem: Limestone (CaCO3) reacts with hydrochloric acid according to the equation: CaCO 3 + 2HCl → CaCl2 + H2O + CO2 If 1.00 mol of CO2 has a volume of 22.4 L under the reaction conditions, how many liters of gas can be formed by reaction of 2.30 g of CaCO3 with 2.30 g of HCl? Which reactant is limiting? a. limestoneb. hydrochloric acid 

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Limestone (CaCO3) reacts with hydrochloric acid according to the equation: CaCO 3 + 2HCl → CaCl2 + H2O + CO2 

If 1.00 mol of CO2 has a volume of 22.4 L under the reaction conditions, how many liters of gas can be formed by reaction of 2.30 g of CaCO3 with 2.30 g of HCl? 

Which reactant is limiting? 

a. limestone
b. hydrochloric acid 

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