Using the following standard reduction potentials,
Fe3+ (aq) + e– → Fe2+ (aq) E°red = +0.77 V
Pb2+ (aq) + 2 e– → Pb (s) E°red = –0.13 V
Calculate the standard emf for the following cell reaction as written and determine whether or not the reaction is spontaneous or non‐spontaneous:
Pb2+ (aq) + 2 Fe2+ (aq) → 2 Fe3+ (aq) + Pb (s)
a) –0.90 V, non‐spontaneous
b) –0.90 V, spontaneous
c) +0.90 V, non‐spontaneous
d) –0.64 V, non‐spontaneous
e) +0.64 V, spontaneous
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