H2 (g) + F2 (g) → 2HF (g) ΔH°rxn = - 546.6 kJ
2H2 (g) + O2 (g) → 2H2O (l) ΔH°rxn = - 571.6 kJ
calculate the value of ΔH°rxn for
2F2 (g) + 2H2O (l) → 4HF (g) + O2 (g)
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