Lead(Il) nitrate and ammonium iodide react to form lead(Il) iodide and ammonium nitrate according to the
Pb(NO3)2 (aq) + 2NH4I (aq) → PbI2 (s) + 2NH4NO3 (aq)
a) What volume of a 0.370 M NH 4l solution is required to react with 429 mL of a 0.140 M Pb(NO3)2 solution?
b) How many moles of Pbl2 are formed from this reaction?
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