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Solution: The enthalpy of decomposition of NO2Cl is -114 kJ. Use the following data to calculate the heat of formation of NO2Cl from N2, O2, and Cl2: NO2Cl (g) → NO2 (g) + 1/2Cl2(g)    ΔH°rxn = -114 kJ 1/2 N2 (g) + O2 (g) → NO2 (g)    ΔH°f = 33.2 kJ 1/2 N2 (g) + O2 (g) + 1/2 Cl2 (g) → NO2Cl (g)    ΔH°f  = ?

Problem

The enthalpy of decomposition of NO2Cl is -114 kJ. Use the following data to calculate the heat of formation of NO2Cl from N2, O2, and Cl2

NO2Cl (g) → NO2 (g) + 1/2Cl2(g)    ΔH°rxn = -114 kJ 1/2 

N2 (g) + O2 (g) → NO2 (g)    ΔH°f = 33.2 kJ 

1/2 N2 (g) + O2 (g) + 1/2 Cl2 (g) → NO2Cl (g)    ΔH°f  = ?

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