Solution: The following chemical reaction was performed and the concentration of CCl4 was measured over time. Cl2 (g) + CHCl3 (g) → HCl (g) + CCI (g) The [CCl4] after 9 s was 0.153 mo/L. After 138 s, the [CCl4]

The following chemical reaction was performed and the concentration of CCl₄ was measured over time. 

Cl₂ (g) + CHCl₃ (g) → HCl (g) + CCI (g) 

The [CCl₄] after 9 s was 0.153 mo/L. After 138 s, the [CCl₄] was 0.374 mol/L. Calculate the rate of reaction.