🤓 Based on our data, we think this question is relevant for Professor Bushey's class at TOWSON.
What is the concentration (M) of lithium ions in 4.57 L of a 2.35 M Li 3P solution?
a. 45.0 M
b. 14.1 M
c. 2.35 M
d. 7.05 M
e. 99.0 M
We’re being asked to calculate the molarity (M) of lithium ions (Li+) in 4.57 L of 2.35 M Li3P solution. Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:
Since the Li3P is an ionic compound, it forms ions when dissociating in water. The dissociation of Li3P in water is as follows:
Li3P(s) → 3 Li+(aq) + P–3(aq)