Problem: What is the concentration (M) of lithium ions in 4.57 L of a 2.35 M Li  3P solution?a. 45.0 Mb. 14.1 Mc. 2.35 Md. 7.05 Me. 99.0 M 

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We’re being asked to calculate the molarity (M) of lithium ions (Li+) in 4.57 L of 2.35 M Li3P solution. Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:



Since the Li3P is an ionic compound, it forms ions when dissociating in water. The dissociation of Li3P in water is as follows:

Li3P(s)  3 Li+(aq) + P–3(aq)


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Problem Details

What is the concentration (M) of lithium ions in 4.57 L of a 2.35 M Li  3P solution?

a. 45.0 M

b. 14.1 M

c. 2.35 M

d. 7.05 M

e. 99.0 M 


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