Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: What is the concentration (M) of lithium ions in 4.57 L of a 2.35 M Li  3P solution?a. 45.0 Mb. 14.1 Mc. 2.35 Md. 7.05 Me. 99.0 M 

Solution: What is the concentration (M) of lithium ions in 4.57 L of a 2.35 M Li  3P solution?a. 45.0 Mb. 14.1 Mc. 2.35 Md. 7.05 Me. 99.0 M 

Problem

What is the concentration (M) of lithium ions in 4.57 L of a 2.35 M Li  3P solution?

a. 45.0 M

b. 14.1 M

c. 2.35 M

d. 7.05 M

e. 99.0 M 


Solution

We’re being asked to calculate the molarity (M) of lithium ions (Li+) in 4.57 L of 2.35 M Li3P solution. Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:



Since the Li3P is an ionic compound, it forms ions when dissociating in water. The dissociation of Li3P in water is as follows:

Li3P(s)  3 Li+(aq) + P–3(aq)


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