# Problem: What is the concentration (M) of lithium ions in 4.57 L of a 2.35 M Li  3P solution?a. 45.0 Mb. 14.1 Mc. 2.35 Md. 7.05 Me. 99.0 M

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We’re being asked to calculate the molarity (M) of lithium ions (Li+) in 4.57 L of 2.35 M Li3P solution. Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words: Since the Li3P is an ionic compound, it forms ions when dissociating in water. The dissociation of Li3P in water is as follows:

Li3P(s)  3 Li+(aq) + P–3(aq)

82% (121 ratings) ###### Problem Details

What is the concentration (M) of lithium ions in 4.57 L of a 2.35 M Li  3P solution?

a. 45.0 M

b. 14.1 M

c. 2.35 M

d. 7.05 M

e. 99.0 M

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Our tutors have indicated that to solve this problem you will need to apply the Molarity concept. You can view video lessons to learn Molarity. Or if you need more Molarity practice, you can also practice Molarity practice problems.

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