Ch.16 - Aqueous Equilibrium WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The molar solubility of Ba3(PO4)2 is 8.89 x 10-9 M in pure water. Calculate the Ksp for Ba3(PO4)2. a. 4.94 x 10-49 M b. 5.55 x 10-41 M c. 8.16 x 10-31 M d. 6.00 x 10-39 M 

Problem

The molar solubility of Ba3(PO4)2 is 8.89 x 10-9 M in pure water. Calculate the Ksp for Ba3(PO4)2

a. 4.94 x 10-49

b. 5.55 x 10-41

c. 8.16 x 10-31

d. 6.00 x 10-39