Problem: If 250 mL of methane, CH4, effuses through a small hole in 28 s, the time required for the same volume of helium to pass through the hole under the same conditions will be 

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FREE Expert Solution

We’re being asked to calculate the time required for 250 mL of helium (He) gas to effuse through a hole. The same volume of methane (CH4) gas took 28 s to effuse through the same hole.


Recall that Graham's Law of Effusion allows us to compare the rate of effusion of two gases. Graham's Law states that the rate of effusion of a gas is inversely proportional to its molar mass.



This means that when comparing two gases:



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Problem Details

If 250 mL of methane, CH4, effuses through a small hole in 28 s, the time required for the same volume of helium to pass through the hole under the same conditions will be 



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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Effusion concept. You can view video lessons to learn Effusion. Or if you need more Effusion practice, you can also practice Effusion practice problems.

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Based on our data, we think this problem is relevant for Professor Keller's class at MIZZOU.