We will calculate the amount of hydrogen gas (H_{2(g)}) produced by Al_{(s)} using the balanced reaction equation.

**Balanced reaction equation: 2 Al _{(s)} + 6 HCl_{(aq)} → 2 AlCl_{3(aq)} + 3 H_{2(g)}**

Since we need to find the **volume of H _{2(g)}** produced and the temperature and pressure (

**STP** means Standard Temperature and Pressure where:

When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced.

2Al (s) + 6HCl (aq) → 2AlCl_{3} (aq) + 3H_{2} (g)

What volume in L of H_{2} (g) is produced when 7.40 g of Al (s) reacts at STP?

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