All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced.2Al (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H2 (g) What volume in L of H2 (g) is produced when 7.40 g of Al (s) reacts at S

Solution: When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced.2Al (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H2 (g) What volume in L of H2 (g) is produced when 7.40 g of Al (s) reacts at S

Problem

When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced.

2Al (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H2 (g) 

What volume in L of H2 (g) is produced when 7.40 g of Al (s) reacts at STP?


Solution

We will calculate the amount of hydrogen gas (H2(g)) produced by Al(s) using the balanced reaction equation. 

Balanced reaction equation:      2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g)


Since we need to find the volume of H2(g) produced and the temperature and pressure (STP) are given, we’re going to use the ideal gas equation:

STP means Standard Temperature and Pressure where:

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