Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
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Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Phosphorous acid dissociates to form dihydrogen phosphite and hydronium ion. Phosphorous acid has Ka of 5.0 x 10-2. Write the equation dissociation for phosphorous acid. Express your answer as a chemi

Solution: Phosphorous acid dissociates to form dihydrogen phosphite and hydronium ion. Phosphorous acid has Ka of 5.0 x 10-2. Write the equation dissociation for phosphorous acid. Express your answer as a chemi

Problem

Phosphorous acid dissociates to form dihydrogen phosphite and hydronium ion. Phosphorous acid has Ka of 5.0 x 10-2

Write the equation dissociation for phosphorous acid. Express your answer as a chemical equation. Identify all of the phases in your answer. 


What is the expression constant dissociation for phosphorous acid? 

a) K= [H2PO3-] / [H3PO3]

b) K= [H3PO3] / [H3O+][H3PO3-]

c) K= [H3O+][H2PO3-] / [H3PO3]

d) K= [H3O+] [H2PO3-] / [H3PO3]2

Solution

First, write the dissociation reaction. We start with the acid and water (solvent) as the reactants. Then the products should be the conjugate base (1 less H) and H3O+ ( where the H went).  Take note of the charges. The conjugate base should gain a negative charge. All of the compounds except water (liquid) should be aqueous (aq) since they are dissolved in water. 


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