Calculate the ΔH° for the following reaction using the information below it.
C2H5OH (l) + O2 (g) → CH3CO2H (l) + H2O (l): ΔH° = ?
C2H5OH (l) + 1/2O2 (g) → CH3CHO(l) + H2O(l): ΔH° = -175 kJ
CH3CHO (l) + 1/2O2 (g) → CH3CO2H (l): ΔH° = -318 kJ
(A) 493 kJ
(B) 247 kJ
(C) 143 kJ
(D) -143 kJ
(E) -493 kJ
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