Chemistry Stoichiometry Solution: Aluminum and oxygen react according to the followi...

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Solution: Aluminum and oxygen react according to the following equation: 4Al(s) + 3O 2(g) → 2Al2O3(s) What mass of Al2O3, in grams, can be made by reacting 4.6 g Al with excess oxygen?a. 35b. 8.7c. 1.2d. 17e. 2.4 

Problem

Aluminum and oxygen react according to the following equation: 4Al(s) + 3O 2(g) → 2Al2O3(s) 

What mass of Al2O3, in grams, can be made by reacting 4.6 g Al with excess oxygen?

a. 35

b. 8.7

c. 1.2

d. 17

e. 2.4 


Solution

We’re being asked to calculate the mass of Al2O3, which will be formed by 4.6 g Al with excess O2. Since O2 is in excess, we can simply ignore it in our calculations. The flow for this problem will be like this:


Mass of Al (molar mass of Al)  Moles of Al (mole-to-mole comparison)  Moles of Al2O3 (molar mass of Al2O3)  Mass of Al2O3


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