Ch.3 - Chemical ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Aluminum and oxygen react according to the following equation: 4Al(s) + 3O 2(g) → 2Al2O3(s) What mass of Al2O3, in grams, can be made by reacting 4.6 g Al with excess oxygen?a. 35b. 8.7c. 1.2d. 17e. 2

Solution: Aluminum and oxygen react according to the following equation: 4Al(s) + 3O 2(g) → 2Al2O3(s) What mass of Al2O3, in grams, can be made by reacting 4.6 g Al with excess oxygen?a. 35b. 8.7c. 1.2d. 17e. 2

Problem

Aluminum and oxygen react according to the following equation: 4Al(s) + 3O 2(g) → 2Al2O3(s) 

What mass of Al2O3, in grams, can be made by reacting 4.6 g Al with excess oxygen?

a. 35

b. 8.7

c. 1.2

d. 17

e. 2.4 


Solution

We’re being asked to calculate the mass of Al2O3, which will be formed by 4.6 g Al with excess O2. Since O2 is in excess, we can simply ignore it in our calculations. The flow for this problem will be like this:


Mass of Al (molar mass of Al)  Moles of Al (mole-to-mole comparison)  Moles of Al2O3 (molar mass of Al2O3)  Mass of Al2O3


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