Problem: The freezing point of the noble gas, argon, is -308°F. What is this temperature in kelvins?a. 462 Kb. 462 Kc. -249 Kd. 84 Ke. 120 K
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FREE Expert Solution
Temp in °F = 1.8(°C) + 32
-308 = 1.8(°C) + 32
Problem Details
The freezing point of the noble gas, argon, is -308°F. What is this temperature in kelvins?
a. 462 K
b. 462 K
c. -249 K
d. 84 K
e. 120 K
