Problem: The freezing point of the noble gas, argon, is -308°F. What is this temperature in kelvins?a. 462 Kb. 462 Kc. -249 Kd. 84 Ke. 120 K 

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Temp in °F = 1.8(°C) + 32

-308 =  1.8(°C) + 32

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The freezing point of the noble gas, argon, is -308°F. What is this temperature in kelvins?

a. 462 K

b. 462 K

c. -249 K

d. 84 K

e. 120 K 

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