Ch.14 - Chemical EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Consider the formation of hydrogen fluoride: H2 (g) + F2 (g) <-> 2HF (g) If a 3.0 L nickel reaction container (glass cannot be used because it reacts with HF) filled with 0.0055 M H2 is connecte

Problem

Consider the formation of hydrogen fluoride: 

H2 (g) + F2 (g) <-> 2HF (g) 

If a 3.0 L nickel reaction container (glass cannot be used because it reacts with HF) filled with 0.0055 M H2 is connected to a 3.4 L container filled with 0.033 M F 2. The equilibrium constant. Kp, is 7.8 x 1014. Calculate the molar concentration of HF at equilibrium.