Molarity can be calculated as:
For this problem, we are given the mass of AlCl3, we can calculate the moles by using its molar mass which is:
MM of AlCl3:
Al - 26.98 (1) = 26.98
Cl - 35.45 (3) = 106.36
26.98 + 106.35 = 133.34 g/mol
A chemist prepares a solution of aluminum chloride (AICI 3) by measuring out 24.6 g of aluminum chloride into a 250. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's aluminum chloride solution. Be sure your answer has the correct number of significant digits.
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Our tutors rated the difficulty ofA chemist prepares a solution of aluminum chloride (AICI 3) ...as medium difficulty.
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Based on our data, we think this problem is relevant for Professor Hopkins' class at LSU.