Problem: What is the maximum mass of S 8 that can be produced by combining 86.0 g of each reactant? 8SO2 + 16H2S → 3S8 + 16H2O

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In order to calculate the maximum mass of S that can be produced, we would need to find the limiting reactant. The limiting reactant would produce that maximum amount.

First, we calculate the molar mass of both reactants and  S as preparation for later calculations.

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What is the maximum mass of S 8 that can be produced by combining 86.0 g of each reactant? 

8SO2 + 16H2S → 3S8 + 16H2O


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