All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: A 2.45-L flexible flask at 15°C contains a mixture of N2, He, and Ne at partial pressures of 0.283 atm for N2, 0.151 atm for He, and 0.425 atm for Ne. (a) Calculate the total pressure of the mixture i

Solution: A 2.45-L flexible flask at 15°C contains a mixture of N2, He, and Ne at partial pressures of 0.283 atm for N2, 0.151 atm for He, and 0.425 atm for Ne. (a) Calculate the total pressure of the mixture i

Problem

A 2.45-L flexible flask at 15°C contains a mixture of N2, He, and Ne at partial pressures of 0.283 atm for N2, 0.151 atm for He, and 0.425 atm for Ne. 

(a) Calculate the total pressure of the mixture in atm.



(b) Calculate the volume in liters at STP occupied by He and Ne if the N 2 is removed selectively.



Solution

PART A

To calculate the total pressure we simply get the sum of the partial pressures. 

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