Ch.11 - Liquids, Solids & Intermolecular ForcesWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The fluorocarbon compound C2Cl3F3 has a normal boiling point of 47.6 ºC. The specific heats of C2Cl3F3 (l) and C2Cl3F3(g) are 0.91 J/g.ºK and 0.67 J/g.ºK, respectively. The heat of vaporization for th

Solution: The fluorocarbon compound C2Cl3F3 has a normal boiling point of 47.6 ºC. The specific heats of C2Cl3F3 (l) and C2Cl3F3(g) are 0.91 J/g.ºK and 0.67 J/g.ºK, respectively. The heat of vaporization for th

Problem

The fluorocarbon compound C2Cl3F3 has a normal boiling point of 47.6 ºC. The specific heats of C2Cl3F3 (l) and C2Cl3F3(g) are 0.91 J/g.ºK and 0.67 J/g.ºK, respectively. The heat of vaporization for the compound is 27.49 kJ/mol. 

A. Calculate the heat required to convert 37.5 g of C 2Cl3F3 from a liquid at 12.75 ºC to a gas at 75.10 ºC. Express your answer using two significant figures.