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Solution: Each step in the process below has a 90.0% yield.CH4 + 4Cl2 → CCl4 + 4 HClCCl4 + 2 HF → CCl 2F2 + 2 HClThe CCI4 formed in the first step is used as a reactant in the second step. If 4.50 mol of CH  4 reacts, what is the total amount of HCl (moles) produced? Assume that Cl2 and HF are present in excess.

Problem

Each step in the process below has a 90.0% yield.

CH4 + 4Cl2 → CCl4 + 4 HCl

CCl4 + 2 HF → CCl 2F2 + 2 HCl

The CCI4 formed in the first step is used as a reactant in the second step. If 4.50 mol of CH  4 reacts, what is the total amount of HCl (moles) produced? Assume that Cl2 and HF are present in excess.



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