Learn how to solve problems like this one with our expert tutor.

Problem: Each step in the process below has a 90.0% yield.CH4 + 4Cl2 → CCl4 + 4 HClCCl4 + 2 HF → CCl 2F2 + 2 HClThe CCI4 formed in the first step is used as a reactant in the second step. If 4.50 mol of CH  4 reacts, what is the total amount of HCl (moles) produced? Assume that Cl2 and HF are present in excess.

FREE Expert Solution
83% (455 ratings)
FREE Expert Solution
83% (455 ratings)
View Complete Written Solution
Problem Details

Each step in the process below has a 90.0% yield.

CH4 + 4Cl2 → CCl4 + 4 HCl

CCl4 + 2 HF → CCl 2F2 + 2 HCl

The CCI4 formed in the first step is used as a reactant in the second step. If 4.50 mol of CH  4 reacts, what is the total amount of HCl (moles) produced? Assume that Cl2 and HF are present in excess.



Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Percent Yield concept. If you need more Percent Yield practice, you can also practice Percent Yield practice problems.

What is the difficulty of this problem?

Our tutors rated the difficulty ofEach step in the process below has a 90.0% yield.CH4 + 4Cl2 ...as medium difficulty.

How long does this problem take to solve?

Our expert Chemistry tutor, Sabrina took 5 minutes and 40 seconds to solve this problem. You can follow their steps in the video explanation above.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Geissler's class at CAL.