Solution: Use the standard reaction enthalpies given below to determine ∆Hrxn for the following reactionP4 (g) + 10 Cl2(g) ---> 4PCI5(s)  ∆Hrxn = ?GivenPCI5(s) --> PCl5(s) + Cl2(g) ∆Hrxn = +157 kJP4(g) +

Use the standard reaction enthalpies given below to determine ∆H_rxn for the following reaction

P₄ (g) + 10 Cl₂(g) ---> 4PCI₅(s)  ∆H_rxn = ?

Given

PCI₅(s) --> PCl₅(s) + Cl₂(g) ∆H_rxn = +157 kJ
P₄(g) + 6 Cl₂(g) --> 4 PCl₃(g) ∆H_rxn = -1207 kJ


-2100. kJ
-1050. kJ
-1786 kJ
-1364 kJ
-1835 kJ