Ch.8 - Periodic Properties of the ElementsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The ground-state electron configuration of an Fe2+ ion is 1s2 2s2 2p6 3s2 3p6 3d6.  Therefore Fe2+ is a) diamagnetic. b) paramagnetic with one unpaired electron. c) paramagnetic with two unpaired

Problem

The ground-state electron configuration of an Fe2+ ion is

1s2 2s2 2p6 3s2 3p6 3d6

Therefore Fe2+ is

a) diamagnetic.

b) paramagnetic with one unpaired electron.

c) paramagnetic with two unpaired electrons.

d) paramagnetic with three unpaired electrons.

e) paramagnetic with four unpaired electrons.