Ch.11 - Liquids, Solids & Intermolecular ForcesWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The specific heat of water is 1.00 cal/g C, the heat of vaporization of water is 540 cal/g, and the heat of fusion of water is 80 cal/g.  How much heat would be required to convert 10 grams of ice at

Solution: The specific heat of water is 1.00 cal/g C, the heat of vaporization of water is 540 cal/g, and the heat of fusion of water is 80 cal/g.  How much heat would be required to convert 10 grams of ice at

Problem

The specific heat of water is 1.00 cal/g C, the heat of vaporization of water is 540 cal/g, and the heat of fusion of water is 80 cal/g.  How much heat would be required to convert 10 grams of ice at 0 degrees C to 10 grams of water at 75 degrees C? 

Solution

We’re being asked to calculate the amount of heat required to convert 10 g of ice at 0 ˚C to 10 g of water 75 ˚C. There are two heats involved in this problem:

1. q1 which is the heat in melting 10 g of ice at 0 ˚C

2. q2 which is the heat in raising the temperature of 10 g of water from 0 ˚C to 75 ˚C


We need to solve for each heat individually then add them together to get the final answer.


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