Ch.3 - Chemical ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Write the described reaction as a balanced reaction equation: “Lead(II)nitrate solution is added to potassium iodide solution, which results in formation of solid lead(II)iodide while potassium nitrat

Problem

Write the described reaction as a balanced reaction equation: “Lead(II)nitrate solution is added to potassium iodide solution, which results in formation of solid lead(II)iodide while potassium nitrate remains in solution.”

a) PbNO3(soln) + KI(soln) → PbI(solid) + KNO3(soln)

b) Pb(NO3)2 + 2KI → 2PbI + 2KNO3

c) Pb(NO3)2(aq) + KI2(s) → PbI2(s) + K(NO3)2(aq)

d) Pb(NO2)(aq) + 2KI(aq) → PbK 2(s) + I2(NO2)(aq)

e) Pb(NO3)2(aq) + 2KI(aq) → PbI 2(s) + 2KNO3(aq)