The Reaction Quotient Video Lessons

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Problem: Consider the following reaction: H2(g) + I2(g) ⇌ 2 HI(g) A reaction mixture at equilibrium at 175 K contains PH2 = 0.958 atm, PI2 = 0.877 atm, and PHI = 0.020 atm. A second reaction mixture, also at 175 K, contains PH2 = PI2 = 0.614 atm , and PHI = 0.105 atm.a. Is the second reaction in equilibrium? yes/nob. If not, what will be the partial pressure of HI when the reaction reaches equilibrium at 175 K?

FREE Expert Solution

For Part a), we're being asked to determine if the second reaction in equilibrium. We're given the following reaction:

H2(g) + I2(g) ⇌ 2 HI(g)


Step 1: Calculate the equilibrium constant, Kp.

Given at equilibrium:

PH2 = 0.958 atm
PI2 = 0.877 atm
PHI = 0.020 atm.

Kp=productsreactantsKp=(HI)2H2I2Kp=(0.020)2(0.958)(0.877)

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Problem Details

Consider the following reaction: H2(g) + I2(g) ⇌ 2 HI(g) 

A reaction mixture at equilibrium at 175 K contains PH2 = 0.958 atm, PI2 = 0.877 atm, and PHI = 0.020 atm. 

A second reaction mixture, also at 175 K, contains PH2 = PI2 = 0.614 atm , and PHI = 0.105 atm.

a. Is the second reaction in equilibrium? yes/no

b. If not, what will be the partial pressure of HI when the reaction reaches equilibrium at 175 K?

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