According to the following reaction, how many moles of Fe(OH) 2 can form from 175.0 mL of 0.2 M LiOH solution? Assume that there is excess FeCl2.
FeCl2 (aq) + 2LiOH (aq) → Fe(OH) 2 (s) + 2LiCl (aq)
a. 5.03 x 10- 2 moles
b. 1.75 x 10 -2 moles
c. 2.52 x 10 -2 moles
d. 6.49 x 10 -2 moles
e. 3.97 x 10 -2 moles
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