Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: A 25.0-mL sample of 0.125 M pyridine is titrated with 0.100 MHCl. Calculate the pH at 0 mL of added acid. Express your answer using two decimal places.

Solution: A 25.0-mL sample of 0.125 M pyridine is titrated with 0.100 MHCl. Calculate the pH at 0 mL of added acid. Express your answer using two decimal places.

Problem

A 25.0-mL sample of 0.125 M pyridine is titrated with 0.100 MHCl. Calculate the pH at 0 mL of added acid. Express your answer using two decimal places.

Solution

• Pyridine (C5H5N) → neutral amine → weak base

No acid added to the solution yet 

• calculate pH of pyridine before titration (0 mL of acid is added)

Solution BlurView Complete Written Solution