Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: HI(aq) + H2O(l) ⇌ H3O(aq) + I-(aq)Identify each as either a: Bronsted-Lowry acid, Bronsted-Lowry base, conjugate acid, or conjugate base.

Solution: HI(aq) + H2O(l) ⇌ H3O(aq) + I-(aq)Identify each as either a: Bronsted-Lowry acid, Bronsted-Lowry base, conjugate acid, or conjugate base.

Problem

HI(aq) + H2O(l) ⇌ H3O(aq) + I-(aq)

Identify each as either a: Bronsted-Lowry acid, Bronsted-Lowry base, conjugate acid, or conjugate base.

Solution

We are being asked to identify each species in the reaction as either a Bronsted-Lowry acid, Bronsted-Lowry base, conjugate acid, or conjugate base.


Let’s define each term first.

Bronsted-Lowry acid → proton (H+) donor

Conjugate base → one less hydrogen form of the Bronsted-Lowry acid

Bronsted-Lowry base → proton (H+) acceptor

Conjugate acid → one hydrogen greater than Bronsted-Lowry base


Reaction given:      HI(aq) + H2O(l)  H3O+(aq) + I-(aq)

View the complete written solution...