CN– is the conjugate base to the weak acid HCN, with Ka = 6.0 × 10–10, pKa = 9.22.
Given a 50 mL of a 0.1 M of NaCN (which dissociates completely), how many mL of 1.0 M HCl should be added to the solution in order to to bring the pH to 9.22?
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