Ch.12 - SolutionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: A solution was prepared by dissolving 39.0 g of KCl in 225 mL of water.  Calculate the molality of KCl in the solution.

Solution: A solution was prepared by dissolving 39.0 g of KCl in 225 mL of water.  Calculate the molality of KCl in the solution.

Problem

A solution was prepared by dissolving 39.0 g of KCl in 225 mL of water.  Calculate the molality of KCl in the solution.

Solution

We’re being asked to calculate for the molality of the solution prepared by dissolving 39.0 g of KCl in 225 mL of water

 When calculating for molality, we use the following equation:


We will calculate the molality of the solution using the following steps:

Step 1: Calculate the moles of solute.
Step 2: Calculate the mass of the solvent (in kg).
Step 3: Calculate the molality of the solution.


KCl → dissolved in water → Solute

Water (H2O) → where KCl is dissolved → Solvent


Step 1: Calculate the moles of KCl.

Solution BlurView Complete Written Solution