We are asked to find the ratio of the Sn2+ concentrations in the two Sn/Sn2+ half-cells. We will use the Nernst Equation to calculate for the ratio. In the Nernst Equation, we will calculate for Q where Q is equal to [products]/[reactants].
The Nernst Equation at 25°C:
Ecell = cell potential under non-standard conditions
E°cell = standard cell potential
n = number of e- transferred
Q= reaction quotient = [products]/[reactants]
In the Nernst Equation, the E°cell is needed but only Ecell was given. We have to determine the E°cell first and as well as the anode (oxidation) and cathode (reduction) in the concentration cell and the number of electrons transferred (n).
A concentration cell consists of two Sn/Sn2+ half-cells. The cell has a potential of 0.15V at 25°C. What is the ratio of the Sn2+ concentrations in the two half-cells?
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