We’re being asked to calculate the mole fraction of sucrose (C12H22O11) in a solution that is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water.
Sucrose (C12H22O11) → lesser in amount → solute
Water (H2O) → greater in amount → solvent
Mole Fraction (X) relates the moles of solute and solvent within a solution:
We’ll calculate the mole fraction of sucrose using the following steps:
A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the final volume of the solution is 508 mL.
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Based on our data, we think this problem is relevant for Professor Lapeyrouse's class at UCF.