Problem: Given that Ka for HClO is 4.0 × 10–8 at 25°C, What is the value of Kb for ClO– at 25 °C? Kb =____?

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We are being asked to find Kb for ClO-. ClO- is the conjugate base of the weak acid HClO.

    HClO   +      H2O            ClO-      +        H3O+ 
(weak acid)         (base)        (conjugate base)     (conjugate acid) 

Hence, the Kb of ClO- can be calculated from the Ka of HClO.  Ka and Kb are connected by the autoionization constant of water (Kw) in the following equation:

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Given that Ka for HClO is 4.0 × 10–8 at 25°C, What is the value of Kb for ClO at 25 °C? Kb =____?

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